Solution in Python 3 Source Code Link:- ACM ICPC Team (github.com) def acmTeam(topic):
ans = []
for i in range(n):
for j in range(i+1, n):
know=0
for a,b in zip(topic[i], topic[j]):
if a=='1' or b=='1':
know+=1
ans.append(know)
return [max(ans), ans.count(max(ans))] Explanation Firstly, we will declare an empty list called ans, Later on we will store…